The mathematical and logical answer to the question differ.
Enough said on the maths by others in this thread, I would like to explore the logical answer a bit, from the perspective of having "rational players" involved in a WTA game.
Given that, the algorithm of the rational player is "do the move with the best ratio between benefits and risks" one could be tempted to say that the answer to the question could be deterministically given by knowing if - at any given moment and for any given players - there will be a situation in which two possible moves will have the same ratio benefits/risks. The "tempted person" could hence argue that each such case constitute a "fork" in the tree of possible games and thus that the final number of possible configuration will increase exponentially with the number of such possibilities.
In reality further scrutiny will dissuade this "tempted person" to think that way, as the rational player will consider the ratio benefits/risks not only for the turn "X" but also for the options that each option of turn "X" will generate for turn "X+1". A rational player - indeed - should perform this evaluation routine recursively till the end of the game, and then will pick the option in turn X that will generate the option in turn X+1 that will generate the options in turn X+2 ... that will generate the best options in the final turn of the game.
Since each of the 7 rational players will play with the same logic, regardless of how they will estimate benefits and risks, the orders that will be issued in spring 1901 can only be one set that will generate the best options for the future, and all the rest of the game will be determined until the very last turn, in which - should there be more than one options with the same ratio - any of the orders could be given.
So, according to logic, the number of possible "rational outcomes" will be very limited: In the case of many players still be involved in the game, this number could potentially be 1 (as all units will have to defend some SC). In the case of only 2 players left in the last turn, several units will have no active role in getting further SC's or protecting acquired SC's and could therefore move anywhere, generating a few more possibilities (precisely: unit*number_of_options_open_to_that_unit*number_of_units_having_more_than_one_option).
Another interesting point is trying to imagine how this final scenario will look like: will it be a solo victory? a two-ways draw? a seven ways draw? Edi's article suggest it will be a three-way draw, but the premise of that article is that players will not be "rational" (this is for sure a case closer to reality, but it is not the case we are considering).
The answer to that question can be researched by examining the diplomacy Board. In fact, if the board was symmetrical, the logical answer would certainly be: 7 ways-draw. But - luckily - Dip board is everything but symmetrical.
The answer to that question will therefore have to be investigated by studying if the "imbalance" between the geographical strengths of different players are minor enough not to affect significantly the "benefit/risks" ratio of each turn moves.
Should this be the case, a diplomacy "rationally played game" will lead to a 7-ways-draw, and therefore the "rational player's" spring 1901 orders will be:
/draw
The reasoning would vary a bit with a PPSC game, but the outcome would be very similar, indeed.
NOTES:
1. For those interested in the balance of the Dip-board I suggest this serious stuff: http://www.diplom.org/Zine/F1999R/Windsor/dipmap.html
2. For those interested in playing Diplomacy "rationally" I suggest this other less serious article: http://www.diplomacy-archive.com/resources/humour/diplomacy_and_star_trek.htm