when have you ever written the sort symbol with the implied 2

sqrt symbol

you seem to be under the impression that being obtuse is a good thing

it isn't

any solution with a square root in it, including your solution for 8, is invalid if we are not allowed to add numbers, because taking the square root adds a 2 -- sqrt(x) = x^(1/2)

this symbol √ has an implied 2,but to change it to cubed the symbol is the same but you must write the 3 on top

It also equals x^.5 so? I accept that the root symbol means square root unless the 3 or other number is written. You are just being thick to insist what you are.

go read the weed thing in the forum and relax

none of that changes the fact that you have to add a number to use the square root function, which violates one of the original rules

@PE if you no like the game then you no play,,,

I think this game is pretty interesting, but you're breaking your own rules to get a solution and then insisting you aren't, which is obnoxious regardless of what game is being played

@PE, a symbol is not a number, now a symbol can represent a number but it isn't inherently one.

you are entitled to your opinion....you happen to be the only one,and you are still wrong

Could a mod silence PE until he is sober again?

if he's drinking and not sharing,i call bullshit.....you must bring some for everyone in the class

@jmo -- the symbol is another way of saying x^0.5 (or x^(1/2) or whatever) -- at the end of the day it makes no sense to rule out cube roots but not square roots or inversions, all of these add numbers
@ssorenn -- Actually uclabb made the same point I'm making earlier, so I'm not the only one, and you haven't demonstrated anything wrong with my logic, just continued to insist it's incorrect without explanation
@Draugnar -- I'm completely sober, you of all people have no place to be complaining about people being rule-sticklers

@PE the square root symbol when used in math has a 2 above it, you are right. When written without the 2, the same math process will be executed by everyone you could ask to do it.(because it is implied) A cubed root requires the same symbol, but without prompting the equation with a 3 the square would happen. So my statement about not adding a number is true,because it is implied. To be a cubed root you have to write the three. There is no other way

∛ - i was going to say it doesn't exist, but it's in the unicode tables... along with ∜ ∝ ∞ ∃ ∀ ∄ ∫ ⊂ ⊆ ∴ ∼ ∘ (among others)

None of these are 'number' characters which our base 10 system uses.

Also '' 0/0*0=6 ''
PEMDAS applies to 8th grade maths, as per the rules, that means multiplication comes before division, so this is (0 / (0 * 0) ) = (0 / 0) ~ which clearly equals 1 :)
[as X / X = 1 ∀ X ∈ ℤ]

Orthaic, 0/0 =! 1 in general.

PE is so right it's ridiculous. If you are just going to allow arbitrary functions if they "don't have a number in them when I write them", here is a solution for all x:
S(S(S(S(S(S((x - x)/x)))))))
where S is the successor function. That's standard notation. There you go, I solved all of them at once!

is there no 'a' in the expression 'laugh out loud' because you can alternatively say it as 'lol' and everyone will understand what you mean?

that's the equivalent argument you're making and it doesn't make sense

here is another solution using trigonometric functions for arbitrary x:

sec(tan^(-1)(sec(tan^(-1)... repeated 36 times ... (x - x)/x)))))))))))))...))))

Pedants and children...

But I like uclabb's universal solutions.

What if we looked at solutions using integration between limits where the equation had n, and the limit was n to n? Thoughts? Let's get away from the pedantry, k?

I'm going to stay away from the cheap shots here and insist on my original position -- there is nothing pedantic about expecting rules that minimize arbitrariness.

It was a fun light hearted exercise. Let it go. I was the original one who presented using the cube roots on 8 after seeing the square root of 4 and realizing that worked for 9 as well. I let it go. Can't you do the same?

Can't we all just get along?

If you no like, don't play in the playground

We should try to find a solution for every three digit combination. For instance 6 6 5 would be (6*6)^.5)

S(S(S(S(S(S((x - x)/x)))))))

done

^blatantly script-kiddie style stolen without my understanding it

@PE:
S(x) = x+ 1

Now you can understand!

Obviously e is not allowed, and square root is fine but not cube root.

Nice solutions. I'm sorry I missed this.